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Lesson: Chapter 16 — Changes of Matter

16.2. Chemical equations 6 of 7

Practice at balancing

Using the inspection method, let us balance the five equations on page 94. Notice that only the coefficients change in each one.

Unbalanced Balanced equation
Na + O2 → Na2O 4Na + O2 → 2Na2O
Al + O2 → Al2O3 4Al + 3O2 → 2Al2O3
N2 + H2 → NH3 N2 + 3H2 → 2NH3
H2 + O2 → H2O 2H2 + O2 → 2H2O
KClO3 → KCl + O2 2KClO3 → 2KCl + 3O2

Assignment 16.1

The problem

Write balanced chemical equations for the word equations, and state which type of reaction each equation belongs to.

# Balanced equation Type
1 a 2Mg + O2 → 2MgO combination
1 b Zn + CuSO4 → ZnSO4 + Cu single displacement
2 a Mg + 2HCl → MgCl2 + H2 single displacement
2 b FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4 double displacement
3 a CaCO3 → CaO + CO2 decomposition
3 b Fe + S → FeS combination
4 a CaCl2 + Na2CO3 → CaCO3 + 2NaCl double displacement
4 b Fe2O3 + 3CO → 2Fe + 3CO2 reduction — see the note below
5 a 4Na + O2 → 2Na2O combination
5 b 2Na + 2H2O → 2NaOH + H2 single displacement

4 b does not fit the four types neatly

In Fe2O3 + 3CO both reactants are compounds, yet Fe appears as a lone element on the right — so it fits neither the single nor the double displacement pattern exactly. It is better described as a reduction: the CO removes oxygen from the Fe2O3. We meet it again when we come to the extraction of iron.

Show your answers to your teacher and confirm that they are right.