Question 3
What amount of calcium carbonate, in moles, is contained in 10 g of it? (Molar mass: CaCO3 = 100 g mol-1)
The right answer is the one marked above.
0.1 mol. n = 10 g ÷ 100 g mol-1 = 0.1 mol.
10 mol comes from inverting the division and taking 100 ÷ 10. Multiplying instead of dividing gives 1000 mol.