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Lesson: Chapter 7 — Quantification of Elements and Compounds

Working with moles 3 of 10

Question 3

What amount of calcium carbonate, in moles, is contained in 10 g of it? (Molar mass: CaCO3 = 100 g mol-1)

The right answer is the one marked above.

0.1 mol. n = 10 g ÷ 100 g mol-1 = 0.1 mol.

10 mol comes from inverting the division and taking 100 ÷ 10. Multiplying instead of dividing gives 1000 mol.

Answer the question to continue.