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Lesson: Chapter 18 — Work, Energy and Power

18.2. Potential energy 7 of 7

Worked examples on potential energy

Two problems with the same three quantities. The second one gives the mass in grams, which is the only real difficulty in either.

Example 1

The problem

Find the gravitational potential energy of an object of mass 7.5 kg at a height of 4 m.

gravitational potential energy = m g h

= 7.5 kg × 10 m s-2 × 4 m

= 300 J

Example 2

The problem

A fruit on a tree has a mass of 200 g. The vertical height from the ground to that fruit is 4 m. Find the gravitational potential energy of the fruit on the tree.

Figure to be added

Figure for example 2 — a tree with a fruit hanging in it, the 200 g marked against the fruit and a vertical double-headed arrow showing the 4 m from the ground up to it.

mass of the fruit = 200 g = 0.2 kg

gravitational potential energy = m g h

= 0.2 kg × 10 m s-2 × 4 m

= 8 J

Grams have to become kilograms first

200 g is 0.2 kg — divide by 1000. Put 200 straight into the formula and you will get 8000 J, a thousand times too large, and nothing in the answer will look obviously wrong.

The height is measured from where it would land

h is the height above the level the object would fall to — the ground, in both of these. Potential energy is always stated relative to some level, and naming that level is part of stating the answer.