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Lesson: Chapter 13 — Electromagnetism and electromagnetic induction

Transformers 4 of 5

Question 4

An ideal transformer steps 230 V down to 23 V. The secondary current is 10 A. What is the primary current?

The right answer is the one marked above.

1 A. 230 × IP = 23 × 10 = 230 W, so IP = 1 A.

Answer the question to continue.