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Lesson: Chapter 2 — Motion in a Straight Line

2.7. Acceleration due to gravity 2 of 3

An object falling freely

Suppose an object falling vertically from rest takes 4 seconds to reach the ground. Here is how its velocity changes on the way down.

Second by second

velocity as the fall begins = 0

after 1 second = 9.8 m s−1

after 2 seconds = 19.6 m s−1

after 3 seconds = 29.4 m s−1

after 4 seconds, as it hits the ground = 39.2 m s−1

Each step adds another 9.8 — which is precisely what g means.

The graph

t (s) 0 1 2 3 4
v (m s⁻¹) 0 9.8 19.6 29.4 39.2

The velocity increases uniformly, so the graph is a straight line. The shaded region is the height the object fell.

Calculating the height

Method 1 — by formula

average velocity = (0 + 39.2) ÷ 2 = 19.6 m s−1

displacement = average velocity × time

= 19.6 m s−1 × 4 s = 78.4 m

Method 2 — from the graph

The area of the triangle under the line:

(39.2 × 4) ÷ 2 = 78.4 m

The same answer. The graph is not new physics — it is the same calculation seen as geometry.

Extra knowledge — air resistance

The calculation above ignores air resistance. That is why, in the real world, a feather and a stone do not fall at the same rate. For a dense object such as a stone or a fruit, though, this calculation gives a good approximation.