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Lesson: Chapter 15 — Fluid Pressure and Its Applications

15.4. Gas and atmospheric pressure 7 of 8

From centimetres of mercury to pascals

"76 cm Hg" can be read as a pressure, but it is not a unit of pressure — it is a height. P = hρg converts it into pascals.

The problem

At sea level atmospheric pressure is 76 cm Hg. Taking the density of mercury as 13 600 kg m−3 and the acceleration due to gravity as 10 m s−2,

(i) find the atmospheric pressure in Pa.

(ii) find the height of the water column that atmospheric pressure can balance. (density of water 1000 kg m−3)

Solution (i)

atmospheric pressure = h × ρ × g

P = (76 ÷ 100) m × 13 600 kg m−3 × 10 m s−2

= 103 360 Pa

Solution (ii)

If the height of the water column is h, it must produce that same pressure.

h ρ g = 103 360

h × 1000 × 10 = 103 360

h = 103 360 ÷ 10 000

h = 10.336 m

Why mercury is used

To produce the same pressure, water needs a column over 10 metres tall, while mercury needs only 76 centimetres. The reason is that mercury is 13.6 times as dense as water — so the height needed for the same pressure is 13.6 times smaller.

The value at sea level

The standard value of atmospheric pressure at sea level is 76 cm Hg — that is, the pressure produced by a mercury column 76 cm high, which in pascals is about 103 360 Pa.