Question 7
A force of 5 N is applied perpendicular to a rod at a distance of 0.4 m from the pivot axis. What is the moment of this force about the axis?
The right answer is the one marked above.
2 N m. moment = force × perpendicular distance = 5 N × 0.4 m = 2 N m.
Dividing to get 5 ÷ 0.4 = 12.5, or adding to get 5 + 0.4, are the traps here. It is always a multiplication.