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Lesson: Chapter 11 — Electronics

11.3. The diode and rectification 4 of 4

Full-wave rectification

Activity 11.2

You will need: a bicycle dynamo or laboratory AC generator, four 1N4001 diodes, a centre-zero galvanometer, a 100 Ω rheostat, solder, a soldering iron and wires

  1. Solder the four diodes into a bridge, with anodes and cathodes the right way round.
  2. Connect the rheostat and the centre-zero galvanometer to the bridge as shown.
  3. Connect the dynamo to X and Y and turn it slowly. Watch the galvanometer, and use the rheostat if the deflection is too large.

The observation

The galvanometer deflects one way only: the alternating current has become a direct current.

With four diodes arranged as a bridge, both halves of the alternating current flow the same way through the load. With a battery and an LED (figure 11.12): when X is positive, D1 and D3 are forward biased and D2 and D4 reverse biased; turn the battery round and D2 and D4 conduct instead — and the LED lights both times, with current through it from P to Q.

Figure to be added

Figures 11.12 and 11.13 — a bridge of four diodes feeding an LED, with the current paths for each polarity.
t (cycles) 0.25 0.75 1.25 1.75
V 1 1 1 1

Full-wave rectification

Both halves of the alternating current are made to flow the same way through the load: full-wave rectification.

Exercise 11.2

Explain what the galvanometer showed in activity 11.2, and sketch how its current varies with time.

The answer

In each half-cycle a different pair of diodes conducts, but both pairs send current through the galvanometer the same way. So it deflects one way only, rising and falling twice in every cycle — the full-wave graph above.